Optimal. Leaf size=43 \[ \frac{a^2 x^{m+1}}{m+1}+\frac{2 a b x^{m+8}}{m+8}+\frac{b^2 x^{m+15}}{m+15} \]
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Rubi [A] time = 0.0435868, antiderivative size = 43, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077 \[ \frac{a^2 x^{m+1}}{m+1}+\frac{2 a b x^{m+8}}{m+8}+\frac{b^2 x^{m+15}}{m+15} \]
Antiderivative was successfully verified.
[In] Int[x^m*(a + b*x^7)^2,x]
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Rubi in Sympy [A] time = 7.48904, size = 36, normalized size = 0.84 \[ \frac{a^{2} x^{m + 1}}{m + 1} + \frac{2 a b x^{m + 8}}{m + 8} + \frac{b^{2} x^{m + 15}}{m + 15} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**m*(b*x**7+a)**2,x)
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Mathematica [A] time = 0.0314434, size = 39, normalized size = 0.91 \[ x^m \left (\frac{a^2 x}{m+1}+\frac{2 a b x^8}{m+8}+\frac{b^2 x^{15}}{m+15}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[x^m*(a + b*x^7)^2,x]
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Maple [B] time = 0.009, size = 93, normalized size = 2.2 \[{\frac{{x}^{1+m} \left ({b}^{2}{m}^{2}{x}^{14}+9\,{b}^{2}m{x}^{14}+8\,{b}^{2}{x}^{14}+2\,ab{m}^{2}{x}^{7}+32\,abm{x}^{7}+30\,ab{x}^{7}+{a}^{2}{m}^{2}+23\,{a}^{2}m+120\,{a}^{2} \right ) }{ \left ( 1+m \right ) \left ( 8+m \right ) \left ( 15+m \right ) }} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^m*(b*x^7+a)^2,x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^7 + a)^2*x^m,x, algorithm="maxima")
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Fricas [A] time = 0.238296, size = 115, normalized size = 2.67 \[ \frac{{\left ({\left (b^{2} m^{2} + 9 \, b^{2} m + 8 \, b^{2}\right )} x^{15} + 2 \,{\left (a b m^{2} + 16 \, a b m + 15 \, a b\right )} x^{8} +{\left (a^{2} m^{2} + 23 \, a^{2} m + 120 \, a^{2}\right )} x\right )} x^{m}}{m^{3} + 24 \, m^{2} + 143 \, m + 120} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^7 + a)^2*x^m,x, algorithm="fricas")
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Sympy [A] time = 26.3544, size = 313, normalized size = 7.28 \[ \begin{cases} - \frac{a^{2}}{14 x^{14}} - \frac{2 a b}{7 x^{7}} + b^{2} \log{\left (x \right )} & \text{for}\: m = -15 \\- \frac{a^{2}}{7 x^{7}} + 2 a b \log{\left (x \right )} + \frac{b^{2} x^{7}}{7} & \text{for}\: m = -8 \\a^{2} \log{\left (x \right )} + \frac{2 a b x^{7}}{7} + \frac{b^{2} x^{14}}{14} & \text{for}\: m = -1 \\\frac{a^{2} m^{2} x x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{23 a^{2} m x x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{120 a^{2} x x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{2 a b m^{2} x^{8} x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{32 a b m x^{8} x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{30 a b x^{8} x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{b^{2} m^{2} x^{15} x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{9 b^{2} m x^{15} x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} + \frac{8 b^{2} x^{15} x^{m}}{m^{3} + 24 m^{2} + 143 m + 120} & \text{otherwise} \end{cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**m*(b*x**7+a)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.228667, size = 182, normalized size = 4.23 \[ \frac{b^{2} m^{2} x^{15} e^{\left (m{\rm ln}\left (x\right )\right )} + 9 \, b^{2} m x^{15} e^{\left (m{\rm ln}\left (x\right )\right )} + 8 \, b^{2} x^{15} e^{\left (m{\rm ln}\left (x\right )\right )} + 2 \, a b m^{2} x^{8} e^{\left (m{\rm ln}\left (x\right )\right )} + 32 \, a b m x^{8} e^{\left (m{\rm ln}\left (x\right )\right )} + 30 \, a b x^{8} e^{\left (m{\rm ln}\left (x\right )\right )} + a^{2} m^{2} x e^{\left (m{\rm ln}\left (x\right )\right )} + 23 \, a^{2} m x e^{\left (m{\rm ln}\left (x\right )\right )} + 120 \, a^{2} x e^{\left (m{\rm ln}\left (x\right )\right )}}{m^{3} + 24 \, m^{2} + 143 \, m + 120} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^7 + a)^2*x^m,x, algorithm="giac")
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